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PDF HA17902PJ Data sheet ( Hoja de datos )

Número de pieza HA17902PJ
Descripción Quad Operational Amplifier
Fabricantes Hitachi Semiconductor 
Logotipo Hitachi Semiconductor Logotipo



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HA17902 Series
Quad Operational Amplifier
Description
The HA17902 is an internal phase compensation quad operational amplifier that operates on a single-
voltage power supply and is appropriate for use in a wide range of general-purpose control equipment.
Features
Wide usable power-supply voltage range and single-voltage supply operation
Internal phase compensation
Wide common-mode voltage range and operation for inputs close to the 0 level
Ordering Information
Type No.
HA17902PJ
HA17902FPJ
HA17902FPK
HA17902P
HA17902FP
HA17902
Application
Car use
Industrial use
Commercial use
Package
DP-14
FP-14DA
FP-14DA
DP-14
FP-14DA
DP-14

1 page




HA17902PJ pdf
HA17902 Series
Test Circuits
1. Input offset voltage (VIO), input offset current (IIO), and Input bias current (IIB) test circuit
Rf 5k
RS 50
RS 50
SW1
R 10k
R 10k
+
VCC
Rf 5k SW2
VCM
Vout
V
SW1 SW2 VO
On
Off
On
Off
VO1
VO2
VCM =
1
2
VCC
On Off VO3
Off On VO4
VIO
=
1
VO1
+ Rf /
RS
IIO =
VO2 – VO1
R(1 + Rf / RS)
(mV)
(nA)
IIB =
| VO4 – VO3 |
2 · R(1 + Rf / RS)
(nA)
2. Common-mode rejection ratio (CMR) test circuit
CMR = 20 log VIN · Rf (dB)
VO · RS
Rf 5.0k
RS 50
VCC
+
RS 50 Rf
Vin 5.0k
Vout
3. Supply current (ICC) test circuit
A VCC
Vout
+
5

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HA17902PJ arduino
HA17902 Series
HA17902 Application Examples
The HA17902 is a quad operational amplifier, and consists of four operational amplifier circuits and one
bias current circuit. It features single-voltage power supply operation, internal phase compensation, a wide
zero-cross bandwidth, a low input bias current, and a high open-loop gain. Thus the HA17902 can be used
in a wide range of applications. This section describes several applications using the HA17902.
1. Noninverting Amplifier
Figure 1 shows the circuit diagram for a noninverting amplifier. The voltage gain of this amplifier is
given by the following formula.
Vout = 1 + R2
Vin R1
+Vin
10k
+
R2
10k R1
1M
Vout
Figure 1 Noninverting Amplifier
2. Summing Amplifier
Since the circuit shown in figure 2 applies +V1 and +V2 to the noninverting input and +V3 and +V4 to
the inverting input, the total output will be Vout = V1 + V2 – V3 – V4.
R
100k
+V1
VCC
R Vin(+) +
+V2 100k
100k
HA17902
R
100k
+V3
R
+V4 100k
Vin(–)
R
100 k
Vout
Figure 2 Summing Amplifier
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